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gauravkukreja
Nov4-04, 10:43 AM
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A SQUARE PLATE OF SIDE 5 cm IS ROTATING AROUND ONE OF ITS EDGES. IF THE ANGULAR ACCELARATION OF THE BODY IS 0.2 rad/s/s, FIND THE TORQUE.

ANSWER:2.0 * 10^(-5)
(TWO INTO 10 RAISED TO -5)

ramollari
Nov4-04, 10:54 AM
CHECK OUT THIS PROBLEM

A SQUARE PLATE OF SIDE 5 cm IS ROTATING AROUND ONE OF ITS EDGES. IF THE ANGULAR ACCELARATION OF THE BODY IS 0.2 rad/s/s, FIND THE TORQUE.

ANSWER:2.0 * 10^(-5)
(TWO INTO 10 RAISED TO -5)

You need the MASS of the plate to calculate its rotational inertia I=1/2MR^2.

ramollari
Nov4-04, 10:59 AM
The mass should be given as 80g, right?

Doc Al
Nov4-04, 11:43 AM
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