Second rule of comparison in math series

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SUMMARY

The discussion centers on the second rule of comparison in mathematical series, specifically the relationship between the convergence of series \(\sum{A_n}\) and \(\sum{B_n}\). It is established that if \(\sum{B_n}\) converges, then \(\sum{A_n}\) also converges. Conversely, if \(\sum{A_n}\) diverges, it follows that \(\sum{B_n}\) must also diverge. The discussion seeks clarification on this logical implication and requests a proof to solidify understanding.

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Alem2000
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I can't understand this [tex]\sum{A_n}\leq \sum{B_n}[/tex] having said this

if [tex]\sum{B_n}[/tex] converges so does [tex]\sum{A_n}[/tex], okay that

makes perfect sense but then the second rule of comparison is if [tex]\sum<br /> <br /> {A_n}[/tex] diverges then so does [tex]\sum{B_n}[/tex] diverges too...can

anyone tell me how that makes sense? A proof maybe..?
 
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General result, if P implies Q, then not Q implies not P.

replace P with sum Bn converges and Q sum An converges.
 
Or:

Given [tex]\sum{A_n}[/tex] does NOT converge.

Now assume [tex]\sum{B_n}[/tex] DOES converge. Using the theorem you said "makes perfect sense", what does that tell you about [tex]\sum{A_n}[/tex]
?
 

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