Romperstomper
Nov4-04, 05:22 PM
An electron is accelerated through a potential difference of 240V, what is it's speed?
I used energy conservation to find it.
So, here's what I did:
0 = \frac{1}{2} m\Delta v^2 + q\Delta V
240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2
V = 9.2*10^6 m/s
Is this correct, or am I doing something wrong?
I used energy conservation to find it.
So, here's what I did:
0 = \frac{1}{2} m\Delta v^2 + q\Delta V
240V*(1.6*10^-19C) = \frac{1}{2} * (9.1*10^-31kg )* V^2
V = 9.2*10^6 m/s
Is this correct, or am I doing something wrong?