Edin_Dzeko
Jul26-11, 12:55 AM
1. The problem statement, all variables and given/known data
A laser used to dazzle the audience in a rock concert emits green light with a wave length of 515 nm. Calculate the frequency of the light.
2. Relevant equations
V = C/Lambdah
3. The attempt at a solution
http://img36.imageshack.us/img36/7982/unledpg.jpg (http://imageshack.us/photo/my-images/36/unledpg.jpg/)
** In the image I forgot to knock off the "nm" after I did the dimensional analysis to convert it to m disregard it***
My answer when I put it in my calculator is what's in the image but the book has the correct answer as: 5.83 x 10^14 s
How did they get 10x^14? If the bases aren't the same what happens to the exponents?
There was another problem which was solved by the book itself:
3.00 x 10^8 m/(s/s) - **(means s cancels out)
---------------------------
4.62 x 10^14 /(s/s) - ** (means s cancels out)
= 6.49 x 10^-7 m (how did they get -7?)!
Btw, I'm doing the wavelength and frequency equation in Chemistry.
A laser used to dazzle the audience in a rock concert emits green light with a wave length of 515 nm. Calculate the frequency of the light.
2. Relevant equations
V = C/Lambdah
3. The attempt at a solution
http://img36.imageshack.us/img36/7982/unledpg.jpg (http://imageshack.us/photo/my-images/36/unledpg.jpg/)
** In the image I forgot to knock off the "nm" after I did the dimensional analysis to convert it to m disregard it***
My answer when I put it in my calculator is what's in the image but the book has the correct answer as: 5.83 x 10^14 s
How did they get 10x^14? If the bases aren't the same what happens to the exponents?
There was another problem which was solved by the book itself:
3.00 x 10^8 m/(s/s) - **(means s cancels out)
---------------------------
4.62 x 10^14 /(s/s) - ** (means s cancels out)
= 6.49 x 10^-7 m (how did they get -7?)!
Btw, I'm doing the wavelength and frequency equation in Chemistry.