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primarygun
Nov8-04, 03:31 AM
Cu(s)+2H+(aq)----> Cu2+ (aq) + H2 (g)
Do we have this reaction?
If yes, is it a displacement reaction?
If no, is something about the oxiding power of particles?
Could you explain it to me ?
Best regards
HallsofIvy
Nov8-04, 06:42 AM
I see no reaction here at all! You start with separate Copper and Hydrogen and you end with separate Copper and Hydrogen. Are you counting 2Cu--> Cu2 and 2H--> H2 as "reactions"?
It's an ionic equation! Actually, it is supposed to like this:
2Cu (s) + 2H+ (aq) = Cu2+ (aq) + H2 (g)
I can't exactly recall where I've seen this.
primarygun
Nov9-04, 02:53 AM
Does this reaction exist?
Isn't copper being oxidized?
Is this not an oxidation-reduction reaction?
Am I really that bad at chemistry?
:rofl:
primarygun
Nov9-04, 03:15 AM
In my mind, I'm quite sure it is not a displacement reaction.
Hydrogen is above copper in the reactivity series.
I haven't learnt any oxid redox reaction so far, so I want to consult about the concept of it.
Less reactive still can reduce more reactive metal in redox reaction?
I don't think this reaction is possible.
Copper metal will not oxidize when put in H+ ions, it will reduce because it is a stronger oxidizing agent.
The two half-cells:
Cu2+ + 2e- -> Cu
H2 -> 2H+ + 2e-
And together:
Cu2+ + H2 -> Cu + 2H+
This reaction WILL occur, the one you gave WILL NOT.
Take my info with a grain of salt though. I do Physics/Astronomy, not Chemistry. But I do have a background in chem, so I'm not clueless.
primarygun
Nov9-04, 03:35 AM
Cu2+ + H2 -> Cu + 2H+
Ya! This is a displacement reaction!
Ya! This is a displacement reaction!
I've never heard it referred to as that, but if that's what your teacher calls it, ok.
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