Diprotons or dineutrons donot exist?

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SUMMARY

Diprotons and dineutrons do not exist as stable bound states due to the effects of electromagnetic repulsion and the principles of nuclear stability. While deuterium, a bound state of one proton and one neutron, is stable, the diproton, which consists of two protons, decays rapidly into deuterium due to its instability. Theoretical searches for dibaryons continue, but current understanding confirms that bound states of two protons or two neutrons are not viable under existing physical laws.

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  • Understanding of nuclear physics concepts, specifically nucleon interactions.
  • Familiarity with the principles of electromagnetic forces and their effects on particle stability.
  • Knowledge of baryon classification and the concept of dibaryons.
  • Basic grasp of quantum mechanics as it relates to particle decay and stability.
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  • Research the stability of deuterium and its implications in nuclear physics.
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This discussion is beneficial for nuclear physicists, students studying particle physics, and researchers interested in the stability of nucleon interactions and the search for new baryonic states.

nelufar
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Can anyone explain why diprotons or dineutrons don't exist,while a bound state of deuteron exist?

Thanks for the help.
 
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It depends at what level your question is. I mean that searches for dibaryons in general are still performed, because there are theoretical motivations. So telling you "those do not exist" is a bit partial...

At least for the diproton, you can easily imagine that this bound state is extremely similar to the deuterium which (for electrical repulsion) is more stable than the diproton. So a diproton would decay very very very rapidely to a deuterium.
 
My question is in context of exitence of a bound state of two nucleons. A bound state of a neutron and proton exist similarly a bound state of two portons or two neutrons does no exist, that is what I have read? So why it cannot exist?
 

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