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Sa7oru
Aug16-11, 07:25 AM
Hi,

There is one step in Ito Isometry proof I don't understand.

Bt(w) represents the position of w at time t, then E[(Btj+1(w)-Btj(w))2] = tj+1 - tj.

Why is the expectation of the square of the difference of 2 positions equal to their time difference?

Any hint, please.

Thank you.

Eynstone
Aug18-11, 05:41 AM
Could you clarify what Bt(w) is & whether it's normally distributed?

snipez90
Aug18-11, 06:34 AM
I'm guessing B_t(w) is Brownian motion, and yes it's normally distributed because its increments, B_t(w) - B_s(w) are normally distributed (~ N(0, t-s)) if s < t. Indeed, this is the precise property that gives the result the OP wants to understand.