Pretty difficult trig proof (identity)..

[iRaid]

1. The problem statement, all variables and given/known data
\frac{sin\theta}{1-cos\theta} - \frac{cot\theta}{1+cos\theta} = \frac{1-cos^{3}\theta}{sin^{3}\theta}


2. Relevant equations
Trig identities..


3. The attempt at a solution
Basically I got to:
\frac{sin\theta+(cos^{2}\theta)(sin\theta)}{sin^{2 }\theta}
1. The problem statement, all variables and given/known data

Is that right up to there, I think not because I cant get passed this lol.


2. Relevant equations



3. The attempt at a solution

[SammyS]

That doesn't look right.

Show how you got your result so we can help you.

[PeterO]

1. The problem statement, all variables and given/known data
\frac{sin\theta}{1-cos\theta} - \frac{cot\theta}{1+cos\theta} = \frac{1-cos^{3}\theta}{sin^{3}\theta}


2. Relevant equations
Trig identities..


3. The attempt at a solution
Basically I got to:
\frac{sin\theta+(cos^{2}\theta)(sin\theta)}{sin^{2 }\theta}
1. The problem statement, all variables and given/known data

Is that right up to there, I think not because I cant get passed this lol.


2. Relevant equations



3. The attempt at a solution

You did notice the cot function did you - or did you misread it as cos?

[PeterO]

I don't think you were supposed to solve the question for the Original Poster!!!!!

[Dr. Seafood]

>_> Oh. Well, I hope my explanation blurb thing helps so that I'm not just blatantly giving the solution without providing any real understanding.

[Mark44]

>_> Oh. Well, I hope my explanation blurb thing helps so that I'm not just blatantly giving the solution without providing any real understanding.PeterO is correct. The Physics Forums rules do not permit a member to post the solution to another member's problem.

[iRaid]

OK, I attached the rest of my work..

[PeterO]

OK, I attached the rest of my work..

In your 5th line, when you took out a factor of sin(theta) in the numerator, it was not a common factor, as it was in the denominator of a couple of the terms.

[iRaid]

In your 5th line, when you took out a factor of sin(theta) in the numerator, it was not a common factor, as it was in the denominator of a couple of the terms.

I see now thanks, I got it. Stupid mistakes.