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raoulduke1
Aug31-11, 02:23 PM
Could someone verify my answer for this question?

13m ladder is leaning against a wall.
If the top of the ladder slips down the wall at a rate of 2m/s.
How fast will the foot be moving away from the wall when the top is 5m from the ground?

My answer:

use pythagoras to set up equation x^2 + y^2 = 13^2

Then I differentiate this implicitly and get the equation 2x dx/dt + 2y dy/t = 0

Then I fill in the values and get 5/6 m/s.

Is this correct?

verty
Aug31-11, 04:34 PM
That is correct. I did it another way though, using a formula for dh/db.