View Full Version : Express in Polar Coordinate
Tarhead
Nov14-04, 10:34 PM
How do I express this in polar coordinates?
(x-h)^2+(y-k)^2= h^2+k^2
It is a circle with k and h greater than 0.
tiger_striped_cat
Nov14-04, 11:04 PM
go to:
http://mathworld.wolfram.com/PolarCoordinates.html
I think the transforms would be
x--> rcos theta
y--> r sin theta
h --> R cos theta'
k --> R sin theta'
4 prameters to describe the points on a shifted circle (shifted orgin because of the k and h terms) in either cartesian or polar coordinates
Not sure, but I think.
James R
Nov15-04, 01:15 AM
In two dimensions, the transformations are:
x = r\cos \theta, \qquad y = r\sin \theta
That's all you need.
tiger_striped_cat
Nov15-04, 02:37 AM
Yeah this makes sense. Sorry for my mistake. You'll only need two variables to plot a 1-d object in a 2d space.
You would need four parameters to specify a shifted circle in either coordinate system. (The k and h parameters will propagate through your transformation.) You could transform this shift into polar coordinates as well (and you would have to if this was a complicated mechanics problem) but you don't even need to bother with this because it is given as a constant.
Hope I didn't mess you up. Sorry again.
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.