View Full Version : Solving a hard equation
mathrocks
Nov15-04, 11:44 AM
I have the given equation: (6^x+6^-x)/6 = 2. How do you solve this?
arildno
Nov15-04, 11:46 AM
1. Multiply your equation with 6^{x}
2. You have now a quadratic equation in the unknown y=6^{x}
As an alternative, use the identity:
Cosh(t)=\frac{e^{t}+e^{-t}}{2}
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