What Does x=--x Mean in Mathematics?

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SUMMARY

The expression x=--x demonstrates the concept of the additive inverse in mathematics. By applying the definition of zero and the properties of multiplication, it is established that the double negation of x results in the original value of x. Specifically, the manipulation of the equation shows that -(-x) equals x, confirming that the additive inverse of the additive inverse returns the original number. This discussion clarifies the mathematical principles behind negation and identity.

PREREQUISITES
  • Understanding of basic algebraic principles
  • Familiarity with additive inverses and multiplicative identities
  • Knowledge of properties of multiplication, specifically associativity
  • Basic comprehension of mathematical notation and operations
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  • Explore the concept of multiplicative identity in various mathematical contexts
  • Learn about the implications of double negation in algebra
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Students of mathematics, educators teaching algebra concepts, and anyone interested in understanding the fundamentals of negation and identity in mathematical expressions.

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x=--x

wtf =/

(this isn't a homework problem but it was brought up today and I'm curious) :confused:
 
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sinas said:
x=--x

wtf =/

(this isn't a homework problem but it was brought up today and I'm curious) :confused:

Well, what do you start with?
If you start with
[tex]-1 \times -1 = 1[/tex]
then
[tex]--x = -1(-1(x))=(-1 \times -1) x= 1 x =x[/tex]
The first equality is by definition, the second because multiplication is associative, the third because you know [itex]-1 \times -1 =1 [/tex] and the last because 1 is the multiplicative identity.<br /> <br /> To see that [tex]-1 \times -1 =1[/tex]:<br /> [tex]\frac{-1}{-1}=1=\frac{1}{1}[/tex]<br /> so<br /> [tex]\frac{-1}{1}=\frac{1}{-1}[/tex]<br /> but<br /> [tex]1=\frac{-1}{-1}=-1 \times \frac{1}{-1}=-1 \times -1[/tex][/itex]
 
It's a bit easier than that.
By definition of zero, x+0=x
By definition of the additive inverse,
x+(-x)=0

--x, that is, (-(-x))
fulfills therefore:
(-x)+(-(-x)=0
Add x on both sides:
x+(-x)+(-(-x))=x, or, since x+(-x)=0, we get:
(-(-x))=x

That is the additive inverse to the additive inverse of x is x itself.
 

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