View Full Version : Is there a DeRham _Homology_?
Hi, I hope this is not too ignorant, but my Algebraic Topology is rusty:
Is there such a thing as DeRham _homology_? I always hear and read about
DeRham cohomology, but I have never heard of DeRham homology. Is there
such a thing?
hunt_mat
Sep9-11, 03:51 AM
DeRahm cohomology is all to do with the cohomology of differential forms, you set up your Meyer-Veotoris sequence via the exterior derivative. There is alway a pairing between homology and cohomology, so I guess that there is that but there is no formal theory called DeRahm homology as far as I am aware.
Why stop there with the (good) question? How about Cech homology?
quasar987
Sep9-11, 11:57 AM
Cech homology exists, but it is not a homology theory in the sense of the Eilenberg-Steenrod axioms. The little book by Hocking and Young talks a bit about it.
lavinia
Sep13-11, 11:36 AM
DeRahm cohomology is all to do with the cohomology of differential forms, you set up your Meyer-Veotoris sequence via the exterior derivative. There is alway a pairing between homology and cohomology, so I guess that there is that but there is no formal theory called DeRahm homology as far as I am aware.
The connection of the De Rham cochain complex to cohomology with real coefficiants is Stokes theorem. So the duality is through the isomorphism with real cohomology.
Hmm, this is an interesting question and is applicable to something I have been thinking about. Apparently there is a notion of Cech homology- but it doesn't satisfy all of the properties you'd like (mainly, it doesn't do well with giving you sequences which should be exact). However, it can be altered, to a thing called (I think) strong homology, which does give a well behaved homology theory and for which cech cohomology is the dual theory.
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