Find Isomorphism: Mapping Ints to Even Ints

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Homework Help Overview

The discussion revolves around finding an isomorphism from the group of integers under addition to the group of even integers under addition. Participants express uncertainty about the concept of defining a map or function and how to apply the hint provided in the textbook.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the function f(x) = 2x as a potential isomorphism and question how to demonstrate its injectivity, surjectivity, and homomorphic property. There is confusion about what it means to "define a map" and how to apply the hint "try n to 2n." Some participants also wonder about the implications of mapping to odd integers.

Discussion Status

Several participants have suggested the function f(x) = 2x and are exploring the necessary properties to establish it as an isomorphism. There is ongoing clarification regarding the definitions and requirements for proving the properties of the function, with some participants expressing their confusion about the mapping process.

Contextual Notes

Participants note that both groups involved are infinite, which raises questions about the nature of their elements and the implications for defining an isomorphism. There is also mention of potential variations in the problem, such as mapping to odd integers, which introduces additional complexity.

semidevil
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find an isomorphism from from the group of integers under addition to the group of even integers under addition.

I know, very simple question, but I don't know what I am doing here...

the hint in the book says to try n to 2n. I thought of that too, since it specificaly says integers to even integers.

the books says to prove injective, surjective, and phi(x,y) = phi(x) phi(y).

so what do I do? start x = 2y and prove x = y?

I think I'm wronng...
 
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You have n to 2n so try defining a function that creates the isomorphism:

f(x) = 2x

Once you have that, the rest follows:

injective: f(x) = y & f(x') = y now show that x = x'
surjective: you know that if y is an even integer then it is equal to 2x for some x, where x is an integer...

the last part is showing that f(x+y) = f(x) + f(y)...
 
nnnnnnnn said:
You have n to 2n so try defining a function that creates the isomorphism:

f(x) = 2x

Once you have that, the rest follows:

injective: f(x) = y & f(x') = y now show that x = x'
surjective: you know that if y is an even integer then it is equal to 2x for some x, where x is an integer...

the last part is showing that f(x+y) = f(x) + f(y)...


I understand by reading the book what all the steps ask me to do, but I don't know what they mean by "define a map or function." Like, what do I map from what to what?

do I do 2x = 2y, and then go through all the steps? what if they ask to find an isomorphism from integers to odd integers, or something? do I do 3x = 3y?

Basically, I don't know what the hint "try n to 2n" means. How am I supposed to use that...

sorry, really newbie at this.
 
semidevil said:
I understand by reading the book what all the steps ask me to do, but I don't know what they mean by "define a map or function." Like, what do I map from what to what?

do I do 2x = 2y, and then go through all the steps? what if they ask to find an isomorphism from integers to odd integers, or something? do I do 3x = 3y?

Basically, I don't know what the hint "try n to 2n" means. How am I supposed to use that...

sorry, really newbie at this.

The map or function is f(x) = 2x...

To map to odd integers use f(x) = 2x+1, this is not a group though because it is not closed: 3+3=6...
 
semidevil said:
I understand by reading the book what all the steps ask me to do, but I don't know what they mean by "define a map or function." Like, what do I map from what to what?

The question asks you to find (define) an isomorphism from [itex]\mathbb{Z}[/itex] to
[itex]2\mathbb{Z}[/itex]:
[tex]f:\mathbb{Z} \rightarrow 2\mathbb{Z}[/tex].
The 'hint' (which basically gives the answer) is: try f(x)=2x.

What you have to check now is:
Injectivity: [itex]f(x)=f(y) \Rightarrow x=y[/itex]
Surjectivity: for every even number y there exist an integer x, such that f(x)=y.
Homomorphic property: f(x+y)=f(x)+f(y).
 
semidevil said:
do I do 2x = 2y
I think that what's confusing you is that both have to have the same number of elements. Since both groups are infinite, it doesn't matter.

Try thinking of it this way: the integers under addition represent how many $2 bills you have and the even integers represent how many $1 bills you have...
 

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