View Full Version : finding isomorphism...
semidevil
Nov17-04, 04:54 PM
find an isomorphism from from the group of integers under addition to the group of even integers under addition.
I know, very simple question, but I dont know what Im doing here......
the hint in the book says to try n to 2n. I thought of that too, since it specificaly says integers to even integers.
the books says to prove injective, surjective, and phi(x,y) = phi(x) phi(y).
so what do I do? start x = 2y and prove x = y?
I think i'm wronng...
nnnnnnnn
Nov17-04, 06:09 PM
You have n to 2n so try defining a function that creates the isomorphism:
f(x) = 2x
Once you have that, the rest follows:
injective: f(x) = y & f(x') = y now show that x = x'
surjective: you know that if y is an even integer then it is equal to 2x for some x, where x is an integer...
the last part is showing that f(x+y) = f(x) + f(y)...
semidevil
Nov17-04, 11:11 PM
You have n to 2n so try defining a function that creates the isomorphism:
f(x) = 2x
Once you have that, the rest follows:
injective: f(x) = y & f(x') = y now show that x = x'
surjective: you know that if y is an even integer then it is equal to 2x for some x, where x is an integer...
the last part is showing that f(x+y) = f(x) + f(y)...
I understand by reading the book what all the steps ask me to do, but I dont know what they mean by "define a map or function." Like, what do I map from what to what?
do I do 2x = 2y, and then go through all the steps? what if they ask to find an isomorphism from integers to odd integers, or something? do I do 3x = 3y?
Basically, I dont know what the hint "try n to 2n" means. How am I supposed to use that....
sorry, really newbie at this.
nnnnnnnn
Nov18-04, 10:28 AM
I understand by reading the book what all the steps ask me to do, but I dont know what they mean by "define a map or function." Like, what do I map from what to what?
do I do 2x = 2y, and then go through all the steps? what if they ask to find an isomorphism from integers to odd integers, or something? do I do 3x = 3y?
Basically, I dont know what the hint "try n to 2n" means. How am I supposed to use that....
sorry, really newbie at this.
The map or function is f(x) = 2x...
To map to odd integers use f(x) = 2x+1, this is not a group though because it is not closed: 3+3=6...
Galileo
Nov18-04, 10:45 AM
I understand by reading the book what all the steps ask me to do, but I dont know what they mean by "define a map or function." Like, what do I map from what to what?
The question asks you to find (define) an isomorphism from \mathbb{Z} to
2\mathbb{Z}:
f:\mathbb{Z} \rightarrow 2\mathbb{Z}.
The 'hint' (which basically gives the answer) is: try f(x)=2x.
What you have to check now is:
Injectivity: f(x)=f(y) \Rightarrow x=y
Surjectivity: for every even number y there exist an integer x, such that f(x)=y.
Homomorphic property: f(x+y)=f(x)+f(y).
nnnnnnnn
Nov18-04, 10:54 AM
do I do 2x = 2y
I think that whats confusing you is that both have to have the same number of elements. Since both groups are infinite, it doesn't matter.
Try thinking of it this way: the integers under addition represent how many $2 bills you have and the even integers represent how many $1 bills you have...
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.