View Full Version : I have a question regarding some steps in a solution
mendem03
Sep23-11, 02:59 PM
Question 1
step 1
=(2^n-1)/2^n + 1/2^(n+1)
step 2
=2(2^n-1)/2^(n+1) + 1/2^(n+1)
step 3
=2^(n +1)-2+1/2^(n+1)
I don't know how steps 2 and 3 where achieved
can someone please help me
mathman
Sep23-11, 03:31 PM
Step 2 is simply 1/2n = 2/2n+1.
Step 3 doesn't look right. Could you clarify the expression?
HallsofIvy
Sep23-11, 06:37 PM
It would help if you told us what the problem is that this is supposed to be the solution to!
mendem03
Sep24-11, 02:05 PM
2^(n +1) -2+1 / 2^(n+1)
this just means that: 2 to the power of (n+1) -2+1 divided by 2 to the power of (n+1)
the next step is
2^(n +1) -1 / 2^(n+1)
mathman
Sep24-11, 04:08 PM
2 to the power of (n+1) -2+1
You need to put in parentheses. It is not clear what -2 and +1 relate to.
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