Romperstomper
Nov20-04, 01:08 AM
Two coils are wrapped around the same cylinder form. When the current in the first coil is decreasing at a rate of -.242A/s, the induced emf in the second coil has a magnitude of .00165 Volts. What is the mutual inductance?
What I did:
E_2 = -M(\frac{d_i_1}{d_t})
.00165/-.242 = -M
.006818H.
The answer given is 1.96H. I went over it several times and I keep coming back to this equation. Am I wrong, or is the book wrong?
What I did:
E_2 = -M(\frac{d_i_1}{d_t})
.00165/-.242 = -M
.006818H.
The answer given is 1.96H. I went over it several times and I keep coming back to this equation. Am I wrong, or is the book wrong?