What is the Kinetic Energy and Work Done for Separated Space Vehicle

Click For Summary
SUMMARY

The discussion centers on the kinetic energy and work done during the separation of a space vehicle of mass m into two pieces, each of mass 0.5m. It is established that the process conserves momentum but does not conserve kinetic energy. The moving piece's speed after separation is determined to be v, not 2v. The kinetic energy (KE) of the moving piece just after separation is calculated to be 1/2mv^2, while the work done by the internal forces during separation is 0 J, as there is no change in kinetic energy.

PREREQUISITES
  • Understanding of the conservation of momentum
  • Knowledge of kinetic energy calculations
  • Familiarity with the work-energy theorem
  • Basic principles of physics related to motion and forces
NEXT STEPS
  • Study the conservation of momentum in inelastic collisions
  • Learn about the work-energy theorem in detail
  • Explore the differences between scalar and vector quantities in physics
  • Investigate the implications of energy conservation in mechanical systems
USEFUL FOR

Students preparing for physics exams, educators teaching mechanics, and anyone interested in understanding the principles of energy and momentum in motion.

pinky2468
Messages
86
Reaction score
0
This is a question from a practice test, so it might also be a test question. For some reason I am tripping myself up on it:

A space vehicle mas m has a speed v. At some instant, it separates into two pieces each of mass 0.5m. One of the pieces is at rest just after the separation.
(A) Does this process:
(a)conserve kinetic energy (b)not conserve total energy (c) the moving piece has a speed 2v (d) not conserve momentum

(B)what is the KE of the moving piece just after the separation:
(C) how much work was done by the internal forces that caused the separation:

For part B and C the multiple choice answers are the same
(a.) 0 J (b). 1/4mv^2 (c.)1/2mv^2 (d.) mv^2 (e.) 2mv^2

Any help on this, my first thought were that (A) the speed is 2v (B) 2mv^2 (C) ? not sure
 
Physics news on Phys.org
Think about this: which is a vector quantity, energy or momentum?
 
Consider that piece that now has the velocity 2v what was its initial velocity

using the work -energy theorem,

[tex]W = \Delta K[/tex]

that your answer for C

your answers for A and B are fine
 

Similar threads

Replies
2
Views
2K
Replies
1
Views
3K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K