Understand Basic Torque Theory & Direction of Force

  • Context: High School 
  • Thread starter Thread starter Tsunoyukami
  • Start date Start date
  • Tags Tags
    Theory Torque
Click For Summary

Discussion Overview

The discussion centers around understanding the basic theory of torque, specifically how to determine the direction of torque caused by a force on an object. Participants explore concepts related to torque calculations, the right-hand rule, and implications of using different definitions of torque in static and dynamic scenarios.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about determining the direction of torque and seeks clarification on clockwise versus counterclockwise rotation.
  • Another participant corrects the torque equation and introduces the right-hand rule for cross products, suggesting it is relevant for understanding torque direction.
  • A participant mentions discomfort with the right-hand rule and questions whether using an incorrect definition of torque would yield a negative resultant torque.
  • There is a discussion about the moment arm and how applying force in different directions affects the resulting torque.
  • One participant suggests that using an improper definition of torque might still yield the same result in static problems, while another clarifies that this depends on what is being calculated.
  • It is noted that for static problems, reversing the sign convention for clockwise and counterclockwise may not matter, but for dynamic problems, the direction of the torque vector is significant.

Areas of Agreement / Disagreement

Participants express differing views on the implications of using an incorrect definition of torque, particularly regarding static versus dynamic scenarios. There is no consensus on the best approach to understanding torque direction, as some participants are comfortable with the right-hand rule while others are not.

Contextual Notes

Limitations include the potential confusion around the definitions of torque and the right-hand rule, as well as the implications of sign conventions in different contexts. The discussion does not resolve these issues, leaving room for further exploration.

Who May Find This Useful

This discussion may be useful for students or individuals seeking to deepen their understanding of torque, particularly in relation to forces and rotational motion in physics.

Tsunoyukami
Messages
213
Reaction score
11
I'm not exactly sure where to ask this question but I would like someone to please help explain to me how to understand which direction a force a will torque on object. That is, how do I determine whether the force will cause it to rotate clockwise or counterclockwise?

I'm not very good at solving even elementary torque problems because this is a huge element of understanding torque.

This is what I know about toruqe so far:

[itex]\tau[/itex] = [itex]\stackrel{\rightarrow}{F}[/itex] x [itex]\stackrel{\rightarrow}{r}[/itex]

|[itex]\tau[/itex]| = |[itex]\stackrel{\rightarrow}{F}[/itex]| |[itex]\stackrel{\rightarrow}{r}[/itex]| sin [itex]\theta[/itex]
 
Physics news on Phys.org
Tsunoyukami said:
This is what I know about toruqe so far:

[itex]\tau[/itex] = [itex]\stackrel{\rightarrow}{F}[/itex] x [itex]\stackrel{\rightarrow}{r}[/itex]
That should be [itex]\tau[/itex] = [itex]\stackrel{\rightarrow}{r}[/itex] x [itex]\stackrel{\rightarrow}{F}[/itex]

Are you familiar with the right hand rule for cross products?

Also, view the animation on this page: Torque

Torque_animation.gif
 
Last edited by a moderator:
I have used the right-hand rule for cross products before (namely in terms of magnetism) but have never been particularly comfortable with it. Also, if I used torque as I have defined it would my resultant torque be negative (is that not a property of the cross product?)

I understand that if you apply a force in one direction to some radius (I believe this is called a moment arm?) it will cause a toruqe in one direction and if you apply a force in the opposite direction to torque, in turn will point in the opposite direction.
 
Tsunoyukami said:
I have used the right-hand rule for cross products before (namely in terms of magnetism) but have never been particularly comfortable with it.
This illustrates the version that I use for any cross product:

120px-R_hand_Rule.png


Here's another illustration specifically for torque: http://hyperphysics.phy-astr.gsu.edu/hbase/tord.html"
Also, if I used torque as I have defined it would my resultant torque be negative (is that not a property of the cross product?)
Yes. Your (incorrect) definition of F x r would be in the opposite direction to r x F.

It may be worth your time to explore this site: http://hyperphysics.phy-astr.gsu.edu/hbase/torcon.html"
 
Last edited by a moderator:
Thank you for these links; I will explore them and ask again if I need any further clarification.

If I were to use my improper definition of torque when considering each and every torque on a given system it would still yield the same result, correct? That is, at least in any static problem since the net torque would be zero. If the problem were not static and I consistently used this definition my final result would have a negative symbol?
 
Tsunoyukami said:
If I were to use my improper definition of torque when considering each and every torque on a given system it would still yield the same result, correct?
That depends on the specific thing you need to figure out.
That is, at least in any static problem since the net torque would be zero.
In that case, no problem. It's equivalent to reversing the sign convention for clockwise versus counterclockwise--doesn't really matter.
If the problem were not static and I consistently used this definition my final result would have a negative symbol?
Depends on what you are asked to find. If you are actually calculating the torque vector, then your result would be in the opposite direction to the actual torque.

For simple problems that are restricted to 2 dimensions (rotation in a single plane), you may not even need the torque vector. Clockwise versus counter-clockwise is often good enough.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 60 ·
3
Replies
60
Views
8K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 37 ·
2
Replies
37
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K