View Full Version : State Space Analyis - the 'B' matrix
Below is a screen shot from state space analysis in "Control Engineering" by Ogata.
http://www.flickr.com/photos/66943862@N06/6230432028/
I am trying to get at 3-20 from 3-18.
Can't the u part of the matrix also be written as
[1/m 0]T instead of [0 1/m]T?
What's the rationale in choosing one over the other?
There is nothing to do to get to 3-20...if you got to 3-18, you are already at 3-20...well, if you got to 3-17 AND 3-18, you are already at 3-20.
3-20 is exactly the same as 3-17 and 3-18 together, it is simply the expresion of the same set of simultaneous equations, but in matrix form:
x1dot = ( 0 )x1 + ( 1 )x2 + ( 0 )u
x2dot = (-k/m)x1 + (-b/m)x2 + (1/m)u
When 3-17 and 3-18 are written as above, it should be clear to you why 3-20 looks the way it does, right?
Keep in mind the orderly manner in which matrix multiplication works, too, in order to answer your question.
There is nothing to do to get to 3-20...if you got to 3-18, you are already at 3-20...well, if you got to 3-17 AND 3-18, you are already at 3-20.
3-20 is exactly the same as 3-17 and 3-18 together, it is simply the expresion of the same set of simultaneous equations, but in matrix form:
x1dot = ( 0 )x1 + ( 1 )x2 + ( 0 )u
x2dot = (-k/m)x1 + (-b/m)x2 + (1/m)u
When 3-17 and 3-18 are written as above, it should be clear to you why 3-20 looks the way it does, right?
Keep in mind the orderly manner in which matrix multiplication works, too, in order to answer your question.
Yes, I got that. My original question was silly!
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