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Find the complex and real part of z:
4z-z(3+i)=-1+3i
I think I am solving for z but Im having problems isolating it. Can some1 help plz.
honestrosewater
Nov24-04, 01:34 AM
Nevermind, sorry for confusing you.
Im not sure how to do that?
vincebs
Nov24-04, 02:44 AM
4z-z(3+i)=-1+3i
Factor out the z: z(4-(3+i) = -i + 3i ---> z(1-i) = -i + 3i
Hope you can figure out the next step (hint: it may involve the complex conjugate)
4z-z(3+i)=-1+3i
Factor out the z: z(4-(3+i) = -i + 3i ---> z(1-i) = -i + 3i
Hope you can figure out the next step (hint: it may involve the complex conjugate)
THANKS SOOOO MUCH Vincebs I got the answer thank you, I couldn't get the answer because I never thought of factoring thanks sooo much. :smile:
The correct answer to this problem is z=-2+i
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