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View Full Version : What is the binding energy in NaCl?


pearapple
Oct18-11, 11:11 PM
1. The problem statement, all variables and given/known data
Each Na atom transfers 1/6 of an electron, on average, to each Cl atom. Estimate the binidng energy of the ionic bonds in NaCl.


2. Relevant equations



3. The attempt at a solution
The answer says to use k*q1*q2 / r, where k is the electric constant, q1 and q2 are the charges, and r is the separation between the charges.

So it gives k*(1/6)e*e / r.

I'm wondering what would happen if it were a different atom. In NaCl, Na has a charge of +1 and Cl has a charge of -1. If I wanted to calculate the binding energy of something with charges that weren't necessarily 1, how would this change?

Borek
Oct19-11, 02:48 AM
This is based on a simple coulomb interactions between point charges.

pearapple
Oct19-11, 04:11 PM
I know. It's the charges of the ions I'm unclear on. I just wanted to know what the answer would look like if the question was about, say MgO instead of NaCl.

Borek
Oct19-11, 04:24 PM
MgO would mean charges +2 and -2. 1/6th is just effect of the geometry, so in the case of MgO I would expect 2/6th.