atsum
Oct26-11, 10:22 PM
Q: A reactor is needed to convert A to R in a liquid reaction. The stoichiomentry is simply A→R and the rate data is given in the table below (P5.21, Levenspiel 1999).
http://i.imgur.com/h4l1G.jpg
For the reactant concentration to drop from CA0 = 1.3 mol/L to CAf =0.3 mol/L, determine,
a) the time required with a batch reactor. (ans: 10.21 min).
b) the volume required for a flow reactor to achieve the same conversion as in (a) and at
a feeding rate of A 1000 mol/h in (1) a PFR, and (2) a CSTR. (ans: PFR V= 130.8 L;
CSTR V = 25.6 L).
c) the volumes of two flow reactors in series with the exit concentration of A from the 1st
reactor xA1= 0.231 (i.e. CA1= 1 mol/L) for (1) 1st PFR +2nd CSTR, and (2) 1st CSTR
+2nd PFR. For both cases, sketch the area for each reactor in the 1/rA-xA plot. (ans: 1,
V1= 38.7 L,V2 17.9 L; 2, V1= 77.0 L, V2 = 85.4 L).
Hints: Plot 1/rA vs. xA, calculate the area under the line, either by measuring the graphical
area or by integration of the trend line equation (which should be a 5th order polynomial).
-------------------
This time, I cannot solve question (C).
I can only calculate the part of CSTR.
For the PER in case (1):
(1000/60)(5.0244) (5.0244 is the area that from xA=0 to 0.230769, 1000/60 is the flow rate from part (B))
=83.74L
My answer is wrong, but I don't know what's wrong with my calculation
http://i.imgur.com/3arZ9.jpg
http://i.imgur.com/h4l1G.jpg
For the reactant concentration to drop from CA0 = 1.3 mol/L to CAf =0.3 mol/L, determine,
a) the time required with a batch reactor. (ans: 10.21 min).
b) the volume required for a flow reactor to achieve the same conversion as in (a) and at
a feeding rate of A 1000 mol/h in (1) a PFR, and (2) a CSTR. (ans: PFR V= 130.8 L;
CSTR V = 25.6 L).
c) the volumes of two flow reactors in series with the exit concentration of A from the 1st
reactor xA1= 0.231 (i.e. CA1= 1 mol/L) for (1) 1st PFR +2nd CSTR, and (2) 1st CSTR
+2nd PFR. For both cases, sketch the area for each reactor in the 1/rA-xA plot. (ans: 1,
V1= 38.7 L,V2 17.9 L; 2, V1= 77.0 L, V2 = 85.4 L).
Hints: Plot 1/rA vs. xA, calculate the area under the line, either by measuring the graphical
area or by integration of the trend line equation (which should be a 5th order polynomial).
-------------------
This time, I cannot solve question (C).
I can only calculate the part of CSTR.
For the PER in case (1):
(1000/60)(5.0244) (5.0244 is the area that from xA=0 to 0.230769, 1000/60 is the flow rate from part (B))
=83.74L
My answer is wrong, but I don't know what's wrong with my calculation
http://i.imgur.com/3arZ9.jpg