divergence and solenoidal vector fields

[MathematicalPhysics]

I want to find which values of n make the vector field

\underline{F} = {|\underline{r}|}^n\underline{r} solenoidal.

So I have to evaluate the divergence of this vector field I think, then show for which values of n it is zero?

Im starting by substituting:

\underline{r} = \sqrt{x^2 + y^2 + z^2}

getting..

\underline{F} = {(x^2 + y^2 + z^2)}^{n/2}\sqrt{x^2 + y^2 + z^2}

How can I extract

\underline{F_x}, \underline{F_y}, \underline{F_z}?

It's probably really simple but I can't see it! Thanks in advance.

[MathematicalPhysics]

Yeah I was being daft, after sleeping on it I came up with:

\underline{F} = [{(x^2 + y^2 + z^2)}^{n/2}x, {(x^2 + y^2 + z^2)}^{n/2}y, {(x^2 + y^2 + z^2)}^{n/2}z]

That's better, yeah?

so
\underline{F}_x = {(x^2 + y^2 + z^2)}^{n/2}x
\underline{F}_y = {(x^2 + y^2 + z^2)}^{n/2}y
\underline{F}_z = {(x^2 + y^2 + z^2)}^{n/2}z

now
\frac{\partial\underline{F}_x}{\partial x} = nx^2{(x^2 + y^2 + z^2)}^{(n/2)-1} + {(x^2 + y^2 + z^2)}^{n/2}

Hmm if n = 0 the first term is zero as required but the second term would become 1. So how can I find the values of n for which this is zero?

[e(ho0n3]

\frac{\partial\underline{F}_x}{\partial x} = nx^2{(x^2 + y^2 + z^2)}^{(n/2)-1} + {(x^2 + y^2 + z^2)}^{n/2}

Hmm if n = 0 the first term is zero as required but the second term would become 1. So how can I find the values of n for which this is zero?

Calculating \nabla \cdot \vec{F} should give you:

3(x^2+y^2+z^2)^{n/2} + n(x^2+y^2+z^2)^{n/2}

Set that equal to zero and solving for n whould give you n = -3 as long as (x^2+y^2+z^2)^{n/2} \ne 0.

I think...

[MathematicalPhysics]

Thanks, I was having trouble simplifying my expression for divF, knowing what I was aiming for gave me the confidence to proceed lol! Cheers,

Matt.

[MathematicalPhysics]

Following on i'm trying to find the value of \lambda which makes

\frac{\lambda\underline{a}}{|\underline{r}|^3} - \frac{(\underline{a}.\underline{r})\underline{r}}{ |\underline{r}|^5}

solenoidal. Where a is uniform.

I think I have to use div(PF) = PdivF + F.gradP (where P is a scalar field and F a vector field)

and grad(a.r) = a for fixed a.

So when calculating Div of the above, there should the a scalar field in there somewhere that I can seperate out?!

I need some pointers please!

[e(ho0n3]

I don't understand what you mean when you say that 'a is uniform'. Fiddle around with the algebra and show me how far you get.

[MathematicalPhysics]

If this is wrong I can post my working (but its tedious to keep latexing my results!)

I get the expression down to \frac{(\lambda -1)a}{x^2+y^2+z^2}

so could I just say that if \lambda = 1 this would give " \underline{F}" say to be zero which implies dF/dx, dF/dy, dF/dz are all zero so divF = 0 which means it is solenoidal?

Thanks for being patient.

edit** is the (lambda -1)a the scalar field P to plug into that formula?

[e(ho0n3]

Where did you get that formula from? It makes no sense to me (i.e. you can't distribute an operator acting on different objects, scalars and vectors in this case). I know it's tedious to show your work but I can't really tell what your doing. For example, you obtained an expression which isn't even a vector!

[MathematicalPhysics]

sorry it was meant to be..

\frac{(\lambda -1)a}{(x^2 + y^2 + z^2)^{3/2}} = \frac{(\lambda -1)a}{|\underline{r}|^3}

I forgot the 3/2 power which didn't make it a vector as you pointed out!