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pd1zz13
Nov13-11, 05:12 PM
Hi,

I am trying to solve the following equation analytically. I think the solution shouldnt be that hard but I'm really rusty on these kind of things.

V' - k*V^-1/2 = 0

where k is constant. Any help is appreciated, got to turn this in tomorrow!

LCKurtz
Nov13-11, 05:15 PM
Try separation of variables.

pd1zz13
Nov13-11, 05:26 PM
ok I apologize I wrote that wrong. The original equation is:

V'' - k*V^-1/2 = 0

I then said u = V' therefore u' = u(du/dV)

so the new equation is :

u(du/dV) = V^-1/2*k

Im a little rusty on separation of variables but I got a u in the final answer which means I have to integrate again since I need the final answer in terms of V.

The goal is to prove k is proportional to V^3/2

Am i doing this right?