tjkubo
Nov17-11, 12:13 PM
If R is a finite ring and its additive group is cyclic, then
R = <r> = {nr : n an integer} for some r in R.
r^2 is in R so r^2 = kr for some integer k.
Does k have to divide the order of R?
R = <r> = {nr : n an integer} for some r in R.
r^2 is in R so r^2 = kr for some integer k.
Does k have to divide the order of R?