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tjkubo
Nov17-11, 12:13 PM
If R is a finite ring and its additive group is cyclic, then
R = <r> = {nr : n an integer} for some r in R.
r^2 is in R so r^2 = kr for some integer k.
Does k have to divide the order of R?

Deveno
Nov17-11, 05:50 PM
the finite field of 5 elements is a ring with a cyclic additive group.

3 generates this ring, and 4= 32= (3)(3), is it the case that 3 divides 5?