Understanding the Relationship Between Newton Scale Readings and Fx=mgcosθ

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Homework Help Overview

The discussion revolves around understanding the relationship between the readings of a Newton scale and the equation Fx=mgcosθ, particularly in the context of a lab experiment involving a cart being pulled at an angle of 70 degrees.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of Fx and the significance of the angle in the context of the Newton scale readings. There are discussions about the forces involved, particularly how the scale reading relates to the weight of the cart and the angle of pull.

Discussion Status

Some participants are providing insights into the forces at play, including the relationship between the vertical and horizontal components of force. There is an ongoing exploration of how to articulate the connection between the Newton scale and the equation, but no consensus has been reached yet.

Contextual Notes

Participants note the specific conditions of the experiment, including the mass of the cart and the angle of 70 degrees, which may influence the interpretation of the forces involved.

jwalant
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PLZ HELP one tough one!

question is like this:

What is the relationship between the Newton scale reading and Fx=mgcosθ?

Newton scale is attached to the cart which is pulled by the Newton scale.. but how do i explain the relationship?
 
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jwalant said:
question is like this:

What is the relationship between the Newton scale reading and Fx=mgcosθ?

Newton scale is attached to the cart which is pulled by the Newton scale.. but how do i explain the relationship?
You could start by explaining the problem properly. What is Fx? What is the angle?

AM
 
the angle is 70.

but it is kinda discussion question. I have done this lab on Angle depending on Work and now i have to find the relationship between Newton scale which is attached end of the cart. When the cart is pulled 0.1m with 0.1 kg it makes angle of 70 on pully.

Now, i know how to calculate Fx, but don't know how to explain the relationship between Newton scale & Fx.
 
here is my thought, Fx=mgcos70 which is the resulting force of the y forces, which is the weight(mg) and the x forces which is the scale pulling pulling on the cart(your adjacent force). so basically you just need a force strong enough to overcome the weight of the cart.

I don't know if that helps, but it's a summary of what's happening
 

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