starbaj12
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from r to R e^(-2r/a)*r^2 dr
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The discussion focuses on simplifying the integral from r to R of e^(-2r/a) * r^2 dr using integration by parts. The method involves applying integration by parts twice, first letting u = r^2 and dv = e^(-2r/a), which leads to du = 2r dr and v = -a/2 e^(-2r/a). The second application of integration by parts results in an integral that simplifies to just e^(-2r/a), making the overall computation more manageable.
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starbaj12 said:from r to R e^(-2r/a)*r^2 dr
Thanks