Easy Problem: Find Area of y = (x^5 + 4x^4)^(1/2) [-4,0]

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Homework Help Overview

The problem involves finding the area of the curve defined by y = (x^5 + 4x^4)^(1/2) over the interval from -4 to 0. Participants express confusion regarding the integration process and the resulting area calculation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss integration steps and question the validity of their results, with some suggesting that the integration limits or methods may have been misapplied. There is a focus on understanding how to correctly evaluate the area under the curve.

Discussion Status

Multiple interpretations of the integration process are being explored, with some participants offering hints and alternative approaches. There is a recognition of discrepancies in results, and participants are actively seeking clarification on their methods and assumptions.

Contextual Notes

Some participants mention confusion regarding the integration limits and the need to consider only the top half of the loop for area calculation. There is also reference to differing answers provided in textbooks and calculators, contributing to the uncertainty in the discussion.

Sombra
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Easy problem... but urgent!

y = (x^5 + 4x^4)^(1/2)

They want me to find the area of this loop, and the boundaries are -4 and 0, but when I integrate it and plug in the -4, I get 0, which is clearly not the case. If you can help, I would love it.
 
Last edited:
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I think you left out the second limit on the integration!
 
Can you post your integrating steps?
That integration is not equal to [tex]0[/tex]
But
[tex]\int_{-4}^{0} \sqrt{x^{5}+4x^{4}} dx = \frac{2048}{105}[/tex]
 
I did:

Integration of (x^5 +4x^4)^(1/2) is 2/3 (x^5 +4x^4)^(3/2)

So 2/3(0 + 0)^(3/2) = 0

0 - [2/3 (-1024 + 1024)^(3/2) = 0

It doesn't work.
 
No, you integrated incorrectly!
 
ok, the answer given in the back of the book is 4096/105. I know that even if that answer is not correct, it is more correct than mine because the area of that loop in the graph is clearly not 0.
 
ok, I think the book is wrong because the calculator said that it was 19.50476233. I still don't know how this works though because... I still get 0.
 
Little hint

[tex]\int_{-4}^{0} \sqrt{x^{5}+4x^{4}} dx[/tex]

[tex]\int_{-4}^{0} x^{2} \sqrt{x+4} dx[/tex]
 
that's how the original problem was set up. I distributed, thinking it would be easier. In any case, I get 0. Thanks
 
  • #10
Post the original problem as the book states it.
 
  • #11
Sketch the graph y^2 = x^4(x+4) and find the area enclosed by the loop.
 
  • #12
That is distinctly different from the problem you first posed - but your integration is still incorrect! :-)
 
  • #13
the boundaries are still -4 and 0, and my answer still comes out to be 0. What is correct? I guess I am not understanding. Please help!
 
  • #14
[tex]\int x^2 \sqrt {x+4} dx = \frac {2 (x+4)^{3/2} (15 x^2 -48 x + 128)}{105}[/tex]
 
  • #15
ok so 2/3(x+4)^3/2, I got that part, but how did you get the other part. I am not familiar with integrating something undistributed unless it follows the f(x) * f'(x) rule. Sorry for all the questions. Thank you so much!
 
  • #16
Use cyclovenom's hint
 
  • #17
Now I am totally lost... I know I have to integrate only the top half of this loop and multiply it by 2 to find the area or it will equal 0. I just do not know how to set up the problem to make it only the top half of the loop.
 
Last edited:
  • #18
You can integrate by parts. You may get a slightly different form than I did because I did some simplification.
 

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