Is Phi an Isomorphism in an Abelian Group?

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Homework Help Overview

The discussion revolves around the properties of a map phi defined on an abelian group G, specifically examining whether phi is an isomorphism and analyzing its kernel. The subject area includes group theory and homomorphisms.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish the kernel of the map phi and conditions for it to be an isomorphism. Some participants question the notation used for the order of elements and suggest starting from definitions.

Discussion Status

Participants are exploring the definitions related to the problem and clarifying notation. There is an acknowledgment of a typo in the original post, and one participant has provided a partial formulation of the kernel. The discussion is ongoing, with some participants indicating they may return later.

Contextual Notes

There is a mention of the need for clarity regarding the order of elements in the group and the relationship between n and the order of the group G. The original poster expresses uncertainty about how to begin addressing the problem.

b0mb0nika
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let G be an abelian group, and n positive integer
phi is a map frm G to G sending x->x^n
phi is a homomorphism

show that
a.)ker phi={g from G, |g| divides n}
b.) phi is an isomorphism if n is relatively primes to |G|

i have no clue how to even start the prob...:-(
 
Last edited:
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If you're using |g| to mean the order of g in G, then you've made a typo in part (a).
 
yes i did..
|g| divides n
sorry about that :)
 
Well, when you have no clue where to begin, the definitions are often a very good place to start.
 
A. Let [itex]x\in G[/itex]. Then [itex]x^n=e \Leftrightarrow O(x)|n \Rightarrow Ker(\phi)=\{g\in G| O(g)|n\}[/itex]

B. I have to go, I might come back later if it isn't solved by then.
 

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