View Full Version : Solving trig equations using Addition formula
studentxlol
Dec4-11, 03:10 PM
1. The problem statement, all variables and given/known data
Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏
2. Relevant equations
sinAcosB+cosAsinB
3. The attempt at a solution
sin(x+∏/6)=2cosx
2cosx=(√3)/2sinx+1/2cosx
How do I solve from here?
micromass
Dec4-11, 03:17 PM
Moved the thread to precalc. Please post in the correct forum next time.
I like Serena
Dec4-11, 04:16 PM
Hi studentxlol! :smile:
Perhaps you can use the following trig identity?
a sin x + b cos x = √(a2+b2) sin(x+ϕ)
where cos ϕ = a/√(a2+b2)
and sin ϕ= b/√(a2+b2)
HallsofIvy
Dec5-11, 02:42 AM
1. The problem statement, all variables and given/known data
Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏
2. Relevant equations
sinAcosB+cosAsinB
3. The attempt at a solution
sin(x+∏/6)=2cosx
2cosx=(√3)/2sinx+1/2cosx
How do I solve from here?
The first, obvious, step is to subtract (1/2) cos(x) from both sides. Then get a tangent.
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