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studentxlol
Dec4-11, 03:10 PM
1. The problem statement, all variables and given/known data

Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏

2. Relevant equations

sinAcosB+cosAsinB

3. The attempt at a solution

sin(x+∏/6)=2cosx

2cosx=(√3)/2sinx+1/2cosx

How do I solve from here?

micromass
Dec4-11, 03:17 PM
Moved the thread to precalc. Please post in the correct forum next time.

I like Serena
Dec4-11, 04:16 PM
Hi studentxlol! :smile:

Perhaps you can use the following trig identity?

a sin x + b cos x = √(a2+b2) sin(x+ϕ)

where cos ϕ = a/√(a2+b2)
and sin ϕ= b/√(a2+b2)

HallsofIvy
Dec5-11, 02:42 AM
1. The problem statement, all variables and given/known data

Solve the equation: sin(x+∏/6)=2cosx for 0≤x≤2∏

2. Relevant equations

sinAcosB+cosAsinB

3. The attempt at a solution

sin(x+∏/6)=2cosx

2cosx=(√3)/2sinx+1/2cosx

How do I solve from here?

The first, obvious, step is to subtract (1/2) cos(x) from both sides. Then get a tangent.