PDA

View Full Version : Tricky Need practice Help plz


aisha
Dec6-04, 11:41 PM
I dont understand these problems well I do but not these ones 9^(x^2+1)=(27)^x (3)^2x
What I have done is changed all the bases to 3 so (3^3)^(x^2+1)=(3^3) (3)^2x but I dont know what to do next I tried solving for x after simplifying the above and got to the point where the exponents simplify to x^2+3=0 not sure if this is right someone plz help me these are exercise problems.

ascky
Dec6-04, 11:46 PM
9^(x^2+1) to (3^2)^(x^2+1), not (3^3)^(x^2+1) :smile:

aisha
Dec6-04, 11:58 PM
9^(x^2+1) to (3^2)^(x^2+1), not (3^3)^(x^2+1) :smile:

Thanks I think I got the answer x=1/2 or x=2

aisha
Dec7-04, 12:13 AM
so are my answers for x right or wrong?

Gokul43201
Dec7-04, 12:14 AM
They're right

Tom McCurdy
Dec7-04, 12:18 AM
Aisha... did you ever go watch the video I sent you ?
the link?

aisha
Dec7-04, 01:41 AM
Aisha... did you ever go watch the video I sent you ?
the link?

YEH IT WAS DISGUSTING, but that guy is only singing to this song that this real famous arabic singer sang, CHEB KHALID the song was called aisha and was in arabic and french but that skinny dude was scary lol.

aisha
Dec7-04, 01:42 AM
They're right
THANKS GOKU