complex amplitude,Feynman diagrams

[Rothiemurchus]

A physical process can be represented by Feynman diagrams, each with a complex amplitude.
Squaring the sum of these amplitudes gives the rate at which a process occurs.
Since a rate can be a frequency,doesn't this imply that before the sum of amplitudes is squared, we are dealing with the square root of a frequency?
Is a complex amplitude just the square root of a frequency,and how can it
be when a frequency is a real number?

[dextercioby]

A physical process can be represented by Feynman diagrams, each with a complex amplitude.
Squaring the sum of these amplitudes gives the rate at which a process occurs.
Since a rate can be a frequency,doesn't this imply that before the sum of amplitudes is squared, we are dealing with the square root of a frequency?
Is a complex amplitude just the square root of a frequency,and how can it
be when a frequency is a real number?

HINT:Write \omega =|M_{1}+M_{2}|^{2} ,where M1and M2 are 2 complex numbers (the scattering probabilitiy amplitudes) and omega is a real number (the frequency).Try to see whether it makes any sense the formula implied by the problem (the one obtained putting radicals of order 2 over both sides of the eq.i posted).My guess is not.

Daniel.