Is there anything wrong with this algebraically?

[tahayassen]

1. The problem statement, all variables and given/known data

http://img220.imageshack.us/img220/7554/daumequation13237539948.png

2. Relevant equations

N/A

3. The attempt at a solution

The denominator is two terms. If I take the reciprocal of both terms, does that change the value?

[JHamm]

You would need to multiply by
\frac{1}{1 + \frac{\sin^2 x}{\cos^2 x}}
Just remember that \displaystyle \frac{1}{A + B} \ne \frac{1}{A} + \frac{1}{B}

[tahayassen]

Ah, thanks for clearing that up.

[genericusrnme]

You could simplify it to

\frac{\frac{Sin(x)}{Cos(x)}}{1+\frac{Sin^2(x)}{Cos ^2(x)}} = Cos(x)Sin(x)
by multiplying by \frac{Cos^2(x)}{Cos^2(x)}
And then that could become Cos(x)Sin(x)=\frac{Sin(2x)}{2}
That's about as simple as you'll be able to get it though