Confusing static equilibrium problem

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SUMMARY

The discussion centers on solving a static equilibrium problem involving a 900-N boy on a ladder with negligible weight resting on a frictionless floor. The first part of the problem, calculating the force exerted by the floor on each leg of the ladder, was solved correctly with a result of 225 N. The second part, determining the tension in the cross brace, remains unresolved, with hints provided regarding the use of torque calculations and trigonometry to find the length of the cross brace.

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barnsworth
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static equilibrium problem

A 900-N boy sits on top of a ladder of negligible weight that rests on a frictionless floor as in http://m.domaindlx.com/barnsworth/physics.JPG. There is a cross brace halfway up the ladder, and the angle at the apex is 30 degrees.

a) What is the force exerted by floor on each leg of the ladder?

b) Find tension in the cross brace.

The first part was simple enough i guess. i did 4F = 900 since net Fy = 0, giving me F = 225 for (a).

Haven't the slightest clue on part (b) though. I don't know where to begin. :cry:

Anyways, thanks for any help in advance.
 
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Hint: The floor exerts a normal force upwards, which creates a torque about the apex.
 
Also, you can calculate the length of the cross Brace using trigoniometry...

then apply the nice hint of Galileo when calculating the torque...

regards
marlon
 

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