An1MuS
Jan3-12, 03:24 PM
I'd like to know the result of deriving both sides of the equation in respect to time
v= \frac {V}{m}
\frac {d}{dt}v=( \frac {d}{dt}) \frac {V}{m}
which gives
\dot v = . . . ?
If you want some backup, this is a very common thermodynamics relation, where V = volume, m = mass and v = specific volume [m3/kg]. In open systems, we want to know mass flow and volumetric flow so we get \dot m [kg/s] and \dot V [m3/s]. I'd like to know if there's such a thing about specific volume as well, and that depends on how you do that derivative.
Best wishes and thanks,
An1MuS
v= \frac {V}{m}
\frac {d}{dt}v=( \frac {d}{dt}) \frac {V}{m}
which gives
\dot v = . . . ?
If you want some backup, this is a very common thermodynamics relation, where V = volume, m = mass and v = specific volume [m3/kg]. In open systems, we want to know mass flow and volumetric flow so we get \dot m [kg/s] and \dot V [m3/s]. I'd like to know if there's such a thing about specific volume as well, and that depends on how you do that derivative.
Best wishes and thanks,
An1MuS