View Full Version : Simplify the square root
songoku
Jan19-12, 02:12 AM
1. The problem statement, all variables and given/known data
Simplify
\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}
2. Relevant equations
\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}
3. The attempt at a solution
\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}
= \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}
Stuck...
1. The problem statement, all variables and given/known data
Simplify
\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}
2. Relevant equations
\sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}
3. The attempt at a solution
\sqrt {10 + \sqrt{24} + \sqrt{40}+\sqrt{60}}
= \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}
Stuck...
Why is it that \sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}\,?
It's because
a+b+2\sqrt{ab}=\sqrt{a}^2+2\sqrt{a}\sqrt{b}+\sqrt{ b}^2\displaystyle=\left(\sqrt{a}+\sqrt{b}\right)^2
Now look at your final expression: \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}\,.
What are the prime factors of 6? ... of 10? ... of 15 ?
Expand (x+y+z)^2\,.
SammyS, you are the greatest square-root simplifier!!!:biggrin:
ehild
songoku
Jan19-12, 08:22 AM
Why is it that \sqrt{a+b+2\sqrt{ab}} = \sqrt{a}+\sqrt{b}\,?
It's because
a+b+2\sqrt{ab}=\sqrt{a}^2+2\sqrt{a}\sqrt{b}+\sqrt{ b}^2\displaystyle=\left(\sqrt{a}+\sqrt{b}\right)^2
Now look at your final expression: \sqrt {10 + 2 \sqrt{6} + 2 \sqrt{10}+ 2 \sqrt{15}}\,.
What are the prime factors of 6? ... of 10? ... of 15 ?
Expand (x+y+z)^2\,.
Thanks :smile:
SammyS, you are the greatest square-root simplifier!!!:biggrin:
ehild
I agree :biggrin::approve:
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