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yxgao
Dec16-04, 02:52 AM
What is the resonance frequency expression for a parallel RLC circuit?

I know that for a series RLC circuit, it is:

w=\frac{1}{\sqrt{LC}}


Is it the same for a parallel RLC circuit? I remember reading somewhere that it was not exactly the same, although it approaches the series RLC expression in a certain limit. What is this limit?

Thanks!
YG

Integral
Dec16-04, 03:55 AM
You can google this sort of thing for yourself.

Parallel Resonance (http://hyperphysics.phy-astr.gsu.edu/hbase/electric/parres.html)

rayjohn01
Dec17-04, 01:18 PM
In general it will be precisely the same because in both instances the reactances of the L and the C must cancel -- in the series circuit jwL + 1/(jwC) = 0
( sum of reactive impedances )
in the parallel circuit 1/(jwL) + jwC = 1/infinity = 0 ( sum of admittances )
they result in the same thing.
If for an instant you put R=0 (series ), or r=infin ( parallel ) then you can see that such a circuit is BOTH series and parallel.
My guess is that Integral got out the wrong side of the bed this morning, but has invested in Google.
Ray.

yxgao
Dec17-04, 11:53 PM
It shouldn't be the same, I don't think. If you read through the site Integral provided, it gives the form for the parallel circuit, which is slightly different, right?

rayjohn01
Dec19-04, 08:10 AM
For the circuit given with individual component resistances ( I was thinking of a simpler circuit) there is difference depending on your view. The circuit is both series and parallel at the same time ( the source impedance is infinite ). The impedance is minimal and of zero rectance as per your equation looking around the series loop.
However from the source viewpoint that is not the case except for r's very small
The expression for resonance ( meaning infinite parallel reactance is
w^2 .L . C = r1/r2 so if r1=r2 the equation is the same.
Ps I may have the r1,r2 reversed but you get the idea.
Ray

rayjohn01
Dec19-04, 03:14 PM
attached is the simple analysis showing the error or ratio of resonances.
Ray

yxgao
Dec20-04, 06:50 PM
Thanks! I really appreciate it!




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