View Full Version : Decay of an element
siddharth
Dec22-04, 12:02 PM
My school textbook says that "The decay of a radioactive element is a random process and does not depend on external factors such as temperature". But if the decay is a random process, how can we accuratley predict the amount of substance after t seconds using the rate law?? Did I miss something?
Gokul43201
Dec22-04, 04:19 PM
Actually, it's because radioactive decay is random that we can derive the rate law. The route is through probability.
Given a radioactive nucleus, you can never tell when the next decay event is going to happen, because it is equally likely to happen any time. So, if you have a large enough radioactive sample, then in any small time interval \Delta t , the number of decay events expected will be proportional to the number of nucleii in the sample.
Or, ~~ lim_{\Delta t \rightarrow 0} (\frac {\Delta N}{\Delta t}) = \frac {dN}{dt}~~ \alpha ~~N
This is exactly what gives you the first-order rate law :
N(t) = N(0)~e^{-kt}
Astronuc
Dec22-04, 09:09 PM
See also - for a discussion of radioactive decay
http://www.physicsforums.com/showthread.php?t=57309
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