PDA

View Full Version : Reflection loss and refractive index


Puchinita5
Feb14-12, 02:20 AM
1. The problem statement, all variables and given/known data

"Calculate the reflection loss when a beam of radiant energy passes through an empty quartz cell assuming the refractive index of quartz is 1.55"


2. Relevant equations

I/I_i = ((n2-n1) / (n2+n1))^2


3. The attempt at a solution


I'm taking the refractive index through the empty cell to be 1 (is that right?)


I/I_i = ((n2-n1) / (n2+n1))^2
= ((1.55-1)/(1.55+1))^2 = 0.047 or 4.7%

The answer in the back of the book is 17.3 %

what am i doing wrong?

Ninty64
Feb15-12, 12:27 AM
If the light is passing through the quartz, how many times does it get refracted?

You are right in assuming the refractive index inside is 1.