Relative Velocity of a Car on a Moving Truck

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SUMMARY

The discussion centers on calculating the speed of a car on a moving truck using the principles of Galilean relativity. The truck travels at 30 miles per hour relative to the ground, while the car, positioned on the truck, moves at 35 miles per hour relative to the truck bed. The correct speed of the car relative to the ground is 65 miles per hour, derived from the addition of velocities formula: V_{a/c} = V_{a/b} + V_{b/c}. This scenario highlights the application of classical mechanics, specifically in non-relativistic contexts.

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  • Understanding of Galilean relativity
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  • Basic knowledge of classical mechanics
  • Concept of reference frames in physics
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion and relativity in classical mechanics.

JackRuby
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I was just asked a physics type question that is puzzling me. Perhaps I'm over thinking it.

Q. Suppose that there is a flat bed truck traveling at 30 miles/hour relative to the ground. The truck has an infinitely long bed. A car (sitting) on the bed is traveling at 35 miles and hour relative to the truck bed (per its speedometer). What is the speed of the car irelative to the ground? Assume that the car is traveling the same direction.

My guess is 65 Mi/hr

What is the technical explanation?
 
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Galilean Relativity

You are correct. It's an example of the "addition of velocities" formula:
[tex]V_{a/c} = V_{a/b} + V_{b/c}[/tex].

This also illustrates what is called Galilean relativity, or how to transform from one moving frame to another.

Note that if the speeds involved are high enough, one must use Einstein's special relativity and a different formula for velocity addition to get an accurate answer.
 
Great!

Thanks...

I appreciate your help.

JR
 

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