What is the Length Integral Problem at Point (1,1)?

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SUMMARY

The Length Integral Problem at Point (1,1) involves finding a curve whose length integral is defined by the equation L = ∫_{1}^{4} √(1 + 1/(4x)) dx. The discussion highlights the connection between differentiation and integration, specifically referencing the line integral of the first kind and its transformation into a Riemann integral format. The final answer to the problem is identified as √(x).

PREREQUISITES
  • Understanding of integral calculus, specifically length integrals.
  • Familiarity with Riemann integrals and their properties.
  • Knowledge of first-order linear ordinary differential equations (LODE).
  • Basic differentiation techniques and their application in integration.
NEXT STEPS
  • Study the derivation of the length integral formula L(C) = ∫_{C} dl.
  • Learn about Riemann integrals and their applications in curve length calculations.
  • Explore first-order linear ordinary differential equations with separable variables.
  • Investigate the relationship between differentiation and integration in calculus.
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Students and educators in calculus, mathematicians focusing on differential equations, and anyone interested in the applications of integral calculus in curve analysis.

ankh
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Hi, could someone help me with this problem.

Find a curve through the point (1,1) whose length integral is
[itex]L = \int_{1}^{4} \sqrt{1+ \frac {1} {4x}} dx[/itex]

Thanks

PS: Is this the right place topost it? I just thought that differentiation is closely connected to integration.
 
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The line integral of the first kind giving the length of the curve C is
[tex]L(C)=:\int_{C} dl[/tex](1)

If the curve "C" is given through the explicit equation
[tex]y=y(x)[/tex](2)
,it can be shown that the formula (1) becomes this Riemann integral
[tex]L(C)=\int_{x_{1}}^{x_{2}} \sqrt{1+(\frac{dy(x)}{dx})^{2}} dx[/tex](3)

Make the analogy between (3) and your formula to find a first order LODE with separable varaibles.

So your posting the problem in the "Diff.eq." subforum was correct... :smile:

Daniel.
 
More of a calc 2 problem.

The answer is sqrt(x).
 

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