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radtad
Jan9-05, 07:10 PM
The base od a solid is a region in the 1st quadrant bounded by the x-axis, y-axis and the line x+2y=8. If cross sections of the solidperpendicular to the x-axis are semicircles, what is the volume of the solid?

How come the answer isnt just the intgegral from 0-8 of 1/2pi(4-x/2)^2

learningphysics
Jan9-05, 07:25 PM
The base od a solid is a region in the 1st quadrant bounded by the x-axis, y-axis and the line x+2y=8. If cross sections of the solidperpendicular to the x-axis are semicircles, what is the volume of the solid?

How come the answer isnt just the intgegral from 0-8 of 1/2pi(4-x/2)^2

That's what it looks like to me. Is it the wrong answer?

radtad
Jan9-05, 07:26 PM
yea according to the answer key its wrong

radtad
Jan9-05, 07:28 PM
choices are
a. 12.566 b. 14.661 c. 16.755 d 67.021 e 134.041

i keep ending up with choice d but the answer key says its choice c

learningphysics
Jan9-05, 08:26 PM
Oh I see now. I misunderstood the problem. I did it by finding the solid after rotating about the x-axis and integrating... But the cross section of this solid is the circle whose diameter is from y=0 to y=4-x/2. We were thinking the cross section was a circle with diameter from y=-(4-x/2) to y=4-x/2. But if we make the radius (4-x/2)/2, then we get the right answer.

0-8 of 1/2pi[1/2(4-x/2)]^2 is correct.

radtad
Jan9-05, 08:31 PM
yea i realized that too thanks