What is the Volume of a Solid with Squares as Cross Sections?

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In summary, the conversation discusses a region R in the first quadrant bounded by the graphs of $y=x$ and $y=x^2$, which serves as the base for a solid with square cross sections perpendicular to the x-axis. The question asks for the volume of this solid, which is determined through an integral and found to be approximately 0.033.
  • #1
karush
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Let R be the region in the first quadrant bounded below by the graph of $y = x^2$ and above by the graph of
$y=x$. R is the base of a solid whose cross sections perpendicular to the x-axis are squares
\item What is the volume of the solid?
A 0.129
B 0.300
C 0.333
D 700
E 1.271ok I didnt understand what "square area" meant
 
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  • #2
I would first write:

\(\displaystyle dV=(x-x^2)^2\,dx=(x^2-2x^3+x^4)\,dx\)

Hence:

\(\displaystyle V=\int_0^1 x^2-2x^3+x^4\,dx=\frac{1}{30}\)

This seems to be none of the given choices.
 
  • #3
probably C 0.033 after adjusting the typo

so that was how the squares is implemented 🐮
 

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