What is the speed of a proton after moving in a uniform electric field?

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SUMMARY

The discussion centers on calculating the final speed of a proton moving in a uniform electric field of 3.0x10^3 N/C. Initially, the proton has a speed of 2.3x10^4 m/s and travels a distance of 0.003 m. The correct approach involves using the force equation F=qE, where the charge of the proton is 1.6x10^-19 C. The acceleration derived from this force is then applied to kinematic equations to determine the final speed.

PREREQUISITES
  • Understanding of electric fields and forces (F=qE)
  • Knowledge of kinematics equations for motion
  • Familiarity with the properties of protons, including charge (1.6x10^-19 C)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation and application of the force equation F=qE
  • Learn about kinematic equations and their applications in physics
  • Explore the concept of electric fields and their effects on charged particles
  • Investigate the properties of protons and other subatomic particles
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and kinematics, as well as anyone interested in the behavior of charged particles in electric fields.

NeoKrypt
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A uniform electric field has a magnitude of 3.0x10^3 N/C. In a vacuum, a proton begins with a speed of 2.3x10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of .003 m.

I try to work out the problem with the equation F=qE to find the acceleration and plug that into a kinematics equation, but I do not have q. Can anyone help?
 
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You are told it is a proton, so it has a charge equal in magnitude to an electron (with opposite sign). 1.6*10^-19 C, I think. You should look it up in your textbook.
 
ah got it! I actually tried that just before I posted on here except I left the negative sign on the charge. Thanks a lot!
 

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