Power: DEL or ABS? Solve Your Problem Here

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Homework Help Overview

The discussion revolves around the interpretation of power calculations in electrical circuits, specifically focusing on the signs associated with current direction and power delivery. Participants are examining the relationship between current direction and power signs using the formula P=IV.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are exploring the implications of current direction on power calculations, questioning the consistency of signs in their calculations. There is a focus on understanding why different scenarios yield different signs for power delivered.

Discussion Status

Some participants are actively questioning the assumptions made in their calculations, while others are suggesting that there may be errors in the textbook's answers. The discussion reflects a mix of confusion and attempts to clarify the underlying principles of power in electrical circuits.

Contextual Notes

There is mention of a potential discrepancy between textbook answers and the participants' calculations, which has led to confusion. Participants are encouraged to stick with consistent conventions regarding current direction to avoid misunderstandings.

DaVinci
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I tried this thread in the Electrical Engineering area and nothing. So, hopefully someone reading this can explain this problem I am having.

We know that current in one direction is equal to its negative in the opposite direction. We also know P=IV for power. We also know that when current is going from + to -, P absorbed is +VI and P delivered = -VI. When you have current going from - to +, Pabs = -VI and Pdel = +VI.

So, you have -3A going from + to - through an element. There is 6V across that element. P=IV = (-3)(6) = -18W. Since the answer is - and current going from + to -, Pdel = -VI so it is -18W delivered. (Is my train of thought the correct way to view this?)

Now, imagine the same problem. You would have 3A going from - to +. So, P=IV=(3)(6) = 18W. Since current going from - to +, Pdel = +VI, so you have 18W delivered.

The signs are different! The book says the answer is P delivered = -18W. In both cases I found that the power is delivered. But the sign is off in the second example leading to an incorrect answer...

Anyone know what the heck is going on?
 
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Have you considered that current has a direction, and could have a negative sign as well?
 
Yes. I said "We know that current in one direction is equal to its negative in the opposite direction."

The problem is EXACTLY that. Once you get the answers to the examples I gave, the sign is messed up and I cannot figure out why.
 
If a current is going from a negtive to the positive what is its sign??

look for your error in the solutions
 
The problem states -3A going from + to -.

This translates to 3A going from - to +, correct?

X amps going in one direction is equal to -X amps going in the opposite direction.
 
DaVinci said:
The problem states -3A going from + to -.

This translates to 3A going from - to +, correct?

X amps going in one direction is equal to -X amps going in the opposite direction.

for the sake of convention stick with the + to - and convert everything from + to - (i mean direction!)to avoid confusion in the future
 
If I do that then the answer is incorrect.

That is what I want to know. Why is the answer incorrect?
 
DaVinci said:
If I do that then the answer is incorrect.

That is what I want to know. Why is the answer incorrect?

It appears that you're double correcting for the direction of the current.
Try always using Pabs=IV and Pdel=-IV.
 
I talked to my professor about this today...

The problem is the textbook has two wrong answers in it. His solutions manual for the text has the correct answers. So, all weekend I spent trying to make the numbers work and confusing myself. Now it is all clear since I found the book was wrong. :)
 

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