What is the acceleration of the cart down the incline?

Click For Summary
SUMMARY

The acceleration of the cart down the incline is determined by the slope of the graph plotting distance (delta X) against the square of time (delta T)^2, which is calculated to be 15 cm/s². This relationship is derived from the kinematics equation s = ut + (1/2)at², where the initial velocity (u) is zero. The slope of the graph directly correlates to the acceleration, confirming that the acceleration is indeed 15 cm/s². This analysis provides a clear method for understanding motion under constant acceleration.

PREREQUISITES
  • Understanding of basic kinematics equations
  • Knowledge of graphing techniques and slope calculation
  • Familiarity with concepts of acceleration and initial velocity
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the kinematics equation s = ut + (1/2)at²
  • Learn how to plot and interpret graphs of motion
  • Explore the concept of slope in relation to physical quantities
  • Investigate real-world applications of constant acceleration in physics
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics and acceleration principles.

KAW008
Messages
1
Reaction score
0
Question: Suppose you have measured the time (delta T) required for a glider to travel several distances (delta X) down an inclined plane. After plotting the data points on a graph of delta X vs. (delta T)^2, you find the slope of the best fitting straight line is 15cm/s^2. What is the acceleration of the cart down the incline?

I am have such difficulty trying to figure out where to start with this problem. I know that slope = rise/run and that Acceleration = the limit of delta V/ delta T, as T goes to zero. If someone could please point me in the right direction to figuring it out, it would be greatly appreciated!
 
Physics news on Phys.org
Do you know the relationship between distance traveled and time under constant acceleration. Ther is a basic kinematics equation here :

[tex]s = ut + \frac{1}{2}at^2[/tex] where s is the distance travelled, u is the initial velocity, a is the (constant) acceleration and t is the time elapsed.

For your problem, you can let the initial velocity be zero (the glider starts at rest). Use the equation to figure out how the acceleration relates to the gradient of the straight line obtained by plotting [tex]s[/tex] vs [tex]t^2[/tex].
 
Last edited:
BTW, I'm fairly certain this doesn't belong in the College section.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
6K
Replies
8
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K