No Name Required
- 29
- 0
Hello,
Ive done the first part of a question which was to derive the equation
[tex]\displaystyle{\theta(t) = \theta_0 \sin(\omega_0t + \phi)}[/tex]
for a pendulum
where [tex]\displaystyle{\omega_0 = \sqrt{\frac{g}{r}}}[/tex] and [tex]\displaystyle{\phi = \sin^{-1} \left(\frac{\theta_1}{\theta_0}\right)}[/tex]
[tex]r = \mbox{length of rod (pendulum)}[/tex]
The next part says
Sketch [tex]\theta(t)[/tex] versus [tex]t[/tex] for the cases [tex]\phi = 0[/tex] and [tex]\displastyle{\phi = \frac{\pi}{2}}[/tex]
How do I do this if i don't know [tex]\theta_0[/tex] or [tex]r[/tex]? I know they are both constant though, does this have a bearing on the situation?
Thankyou
Ive done the first part of a question which was to derive the equation
[tex]\displaystyle{\theta(t) = \theta_0 \sin(\omega_0t + \phi)}[/tex]
for a pendulum
where [tex]\displaystyle{\omega_0 = \sqrt{\frac{g}{r}}}[/tex] and [tex]\displaystyle{\phi = \sin^{-1} \left(\frac{\theta_1}{\theta_0}\right)}[/tex]
[tex]r = \mbox{length of rod (pendulum)}[/tex]
The next part says
Sketch [tex]\theta(t)[/tex] versus [tex]t[/tex] for the cases [tex]\phi = 0[/tex] and [tex]\displastyle{\phi = \frac{\pi}{2}}[/tex]
How do I do this if i don't know [tex]\theta_0[/tex] or [tex]r[/tex]? I know they are both constant though, does this have a bearing on the situation?
Thankyou
Last edited: