Why a timelike vector and a null vector cannot be orthogonal?

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SUMMARY

Timelike vectors and null vectors cannot be orthogonal due to their inherent properties in Minkowski space. A null vector, defined by the equation \( n^{\mu}n_{\mu}=0 \), does not yield a zero scalar product when paired with a timelike vector, which satisfies \( l^{\mu}l_{\mu}<0 \). The scalar product \( l^{\mu}n_{\mu} \) is not equal to zero, confirming that these vectors cannot be orthogonal. The cosine function plays a crucial role in understanding the relationship between these vectors.

PREREQUISITES
  • Understanding of Minkowski space and its geometry
  • Familiarity with 4-vectors in special relativity
  • Knowledge of scalar products and their properties
  • Basic grasp of the cosine function in vector mathematics
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  • Study the properties of Minkowski space and its metrics
  • Learn about the implications of timelike and null vectors in physics
  • Explore the concept of scalar products in vector spaces
  • Investigate the role of the cosine function in vector relationships
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Why a timelike vector and a null vector cannot be orthogonal?
Isn't a null vector orthogonal to any vector, by definition? Anyway, each component of a vector is multiplied by zero, so in the end the sum is zero.
 
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Null 4-vector:
[tex]n^{\mu};n^{2}=:n^{\mu}n_{\mu}=0[/tex] (1)

Timelike 4-vector:
[tex]l^{\mu};l^{2}=:l^{\mu}l_{\mu}<0[/tex] (2)

Prove that
[tex]l^{\mu}n_{\mu} \neq 0[/tex](3)

HINT:Use components and the property of the 'cosine' function.


Daniel.

P.S.Esti varza...
 
HINT:'cosine' appears in the expression of the scalar product between those vectors (space components).Pay attention with the metric...

Daniel.
 

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