Can the Laplace-ian Problem be Simplified?

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Homework Help Overview

The discussion revolves around a complex equation involving the Laplacian operator and its potential simplification. The subject area pertains to quantum mechanics and differential operators.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the possibility of simplifying a given equation by considering the application of the Laplacian operator. There are discussions about the nature of the function Ψ and its implications for the terms involved.

Discussion Status

There is an ongoing exchange of ideas regarding the correct interpretation of the terms in the equation. Some participants are clarifying their assumptions about the application of the differential operator, while others are attempting to reformulate the equation for simplification.

Contextual Notes

Participants are working under the assumption that Ψ is a scalar function, and there is some confusion regarding the application order of the nabla operator. There is a mention of potential misinterpretation of the terms involved.

Raparicio
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Dear Friends,

I have this problem:

[tex]\frac{i\hbar\Psi}{2m}\frac{\partial\nabla\Psi}{\partial t}+(\frac{i\hbar(\nabla\Psi)}{2m}\nabla)\frac{i\hbar(\nabla\Psi)}{2m}[/tex]

... and i'd like to simplify it... is is possible?

best reggards
 
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The only way i can see it,u may write the laplace-ian in the second term.I assume [itex]\Psi[/itex] to be scalar,hence nabla apllied on it would be the gradient and another nabla would mean laplace-ian...It could mean hessian,but i doubt it is the case here...

Daniel.
 
Like this?

want you mean this?

[tex]\frac{i\hbar\Psi}{2m}\frac{\partial\nabla\Psi}{\partial t}+(\frac{i\hbar(\nabla^2\Psi)}{2m})\frac{i\hbar(\nabla\Psi)}{2m}[/tex]
 
No,i mean this:
[tex]\frac{i\hbar}{2m}\Psi \frac{\partial}{\partial t}\nabla \Psi+\frac{i\hbar}{2m}(\nabla\Psi)\frac{i\hbar}{2m}\Delta \Psi[/tex]

Daniel.

P.S.Nabla is an (differential) linear operator which applies to the right ALWAYS...
 
Sorry,it's the same thing as you have written,it's just that i thought u applied that nabla to the left (else you would have written like i did,without changing the order of terms),instead of to the right...

My applogies,if i assumed a wrong thing...

Daniel.
 

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