Are These Physics Assignment Answers Correct?

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SUMMARY

This discussion focuses on solving physics assignment questions related to simple harmonic motion (SHM) and standing waves. The key calculations include determining the frequency of waves in a vibrating rope, angular frequency, maximum speeds of beads, and the maximum forces acting on them. The frequency was calculated as 8.11 Hz, with an angular frequency of 51.0 rad/s for both beads A and C. Maximum speeds were found to be 36.7 m/s for bead A and 17.7 m/s for bead C, while the maximum force on bead A was calculated to be 5.63 N.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Knowledge of wave mechanics and standing waves
  • Familiarity with formulas for frequency, angular frequency, and maximum speed
  • Basic principles of forces acting on masses in motion
NEXT STEPS
  • Study the mathematical derivation of wave speed and frequency relationships
  • Learn about the principles of resonance in physical systems
  • Explore the concepts of amplitude and maximum speed in SHM
  • Investigate the relationship between mass, spring constant, and SHM characteristics
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Students studying physics, particularly those focusing on mechanics and wave phenomena, as well as educators looking for examples of SHM and standing wave problems.

SAIRA123
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Hi to evryone!
It is so nice to know that everyone is really helpful here.
I have got a physics assignment to hand in tomorrow, although I have done it I am not so sure, I just wanted to check if I have done it right or not. U c I didn't attend many lessons in the last couple of weeks, so wasn't to sure about the assignment.
I would be ever so grateful if someone could tackle these questions for me, then I can check whether I have approached them in the right way. THANKYOU

1. A light rope, fixed at each end, is vibrating in a SHM due to waves passing through it. The waves are resonant with the rope and a standing wave has been set up in the rope. There are 3 small beads A, B and C, each of mass 2.10 g.
As the standing wave vibrates inthe rope, the bead A moves a total distance of 720 mm, the bead B remains stationary, while the bead C moves a total distance of 348mm.
The waves are traveling through the rope, which is 1.48m long (between the points of attachment), with a speed of 12.0ms(minus 1)

a) what is the frequency of the waves traveling through the rope?
b) what is the angular frquency for the vibration of;
Bead A Bead C
c) as they vibrate in their SHM, what is the maximum speed of:
Bead A Bead C
d) as the rope vibrates in the standing wave, what is the maximum size of the force which acts on;
Bead A Bead B Bead C

2. A 925 g. mass is hung from a spring and allowed to come to equilbrium. A force of 6.0 N then pulls vertically down the mass. The force causes the spring to stretch by 180mm.
When the mass is released it is observed to execute a uniform single harmonic motion.
Determine:
a) the amplitude of the SHM
b) the acceleration of the mass when it is released
c) the spring constant for the spring
d) the angular frequency of the SHM
e) the maximum speed of the mass as it oscillates
f) the period of the SHM
 
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Saira, folks here won't do the work for you. Instead, show us what your solution is, and they can tell you if you got the answer right or can help point out any mistakes you made.
 


Hi there, I'm happy to help with your physics assignment questions. It sounds like you've put in a lot of effort and just want to make sure you're on the right track. Let's take a look at the questions together.

For question 1, we have a light rope that is vibrating due to resonant waves passing through it. We have three beads, A, B, and C, with different masses and different distances they move as the rope vibrates. We also know the length of the rope and the speed of the waves traveling through it.

a) To find the frequency, we can use the formula f = v/λ, where f is the frequency, v is the speed of the waves, and λ is the wavelength. In this case, we know v = 12.0 m/s and λ = 1.48 m. Plugging these values in, we get f = 12.0/1.48 = 8.11 Hz.

b) The angular frequency is given by ω = 2πf, where ω is the angular frequency and f is the frequency we just found. So for bead A, ω = 2π(8.11) = 51.0 rad/s. For bead C, ω = 2π(8.11) = 51.0 rad/s as well.

c) To find the maximum speed, we can use the formula v_max = ωA, where v_max is the maximum speed, ω is the angular frequency, and A is the amplitude of the SHM. For bead A, v_max = 51.0(0.72) = 36.7 m/s. For bead C, v_max = 51.0(0.348) = 17.7 m/s.

d) The maximum force acting on the beads can be found using the formula F_max = mω²A, where F_max is the maximum force, m is the mass of the bead, ω is the angular frequency, and A is the amplitude. For bead A, F_max = (0.00210)(51.0)²(0.72) = 5.63 N. For bead B, F_max = (0.00210)(51.0)²(0) = 0 N. For bead C, F_max = (0.00210)(51.0)
 

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